Respuesta :
Answer: 19.221 grams of oxygen gas are needed to react completely with 38.442 grams of sulfur dioxide gas.
Explanation:
Given :[tex]SO_2(g)+O_2(g)\rightarrow SO_3(g)[/tex]
After balancing, [tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)[/tex]
[tex]\text{Number of moles}SO_2=\frac{\text{mass of the compound}}{\text{Molecular mass of the compound}}=\frac{38.442 g}{32g/mol}=1.2013 moles[/tex]
According to reaction ,2 moles of [tex]SO_2[/tex] reacts with one mole of [tex]O_2[/tex] then 1.2013 moles of [tex]SO_2[/tex] will react with :
[tex]=\frac{1}{2}\times 1.2013\text{moles of}O_2=0.6006 moles [/tex]
Mass of [tex]O_2[/tex] required =[tex]\text{Number of moles of compound}\times \text{Molecular mass of the compound}=0.6006 moles\times 32g/mol=19.221 g[/tex]
19.221 grams of oxygen gas are needed to react completely with 38.442 grams of sulfur dioxide gas.
