A student is training for the swim team during July and August one summer. She swims one hour every day, while averaging 800 meters each day. Select the graph that correctly shows the total meters swam during the time of her training program.
![A student is training for the swim team during July and August one summer She swims one hour every day while averaging 800 meters each day Select the graph tha class=](https://us-static.z-dn.net/files/d3b/07f31ca7762d3bd9a9b766c5f5f7055a.gif)
![A student is training for the swim team during July and August one summer She swims one hour every day while averaging 800 meters each day Select the graph tha class=](https://us-static.z-dn.net/files/df2/406f4321e4ccf2531bb82656775e8f7b.gif)
![A student is training for the swim team during July and August one summer She swims one hour every day while averaging 800 meters each day Select the graph tha class=](https://us-static.z-dn.net/files/db9/0edb180bf7e4e9380204262c49f403da.gif)
![A student is training for the swim team during July and August one summer She swims one hour every day while averaging 800 meters each day Select the graph tha class=](https://us-static.z-dn.net/files/d23/fc021cd552458375f88641a9eec60d99.jpg)
Step-by-step explanation:
Please find the attachment.
Let x be the number of hours the student swims per day.
We have been that a student swims one hour every day, so in 2 months the student will swim 60 hours.
We are also told that the student swims 800 meters each day. This means that slope of the graph that represents the total meters swam during the time of her training program will be 800.
So in 60 days the student will swim [tex]60\times 800=48,000\text{ meters}[/tex].
We can see from our attached graph that at x equals 60 our y is approximately 48.
Since y-axis represents the number of meters in thousands, so 48 stands for 48,000.
Therefore, attached graph is the right choice.
Answer:
The right answer is c. aka the third imagine on the test.
Step-by-step explanation: