Respuesta :
In the reaction NH3 + NO → N2 +H2O the reactant,products and their coefficients once the reaction is balanced is
Reactants: 4NH3 and 6NO; products 5N2 and 6 H2O
Explanation
The balanced equation is as below
4 NH3 + 6 NO → 5 N2 + 6 H2O
- In a chemical reaction the reactant are written on the left hand side
hence the reactant in reaction above is 4NH3 and 6NO
- Product are written on the right side of a chemical equation
Hence the product in reaction above is 5N2 and 6 H2O
Coefficient is the number in front of a chemical formula
The coefficient in equation above are 4,6,5,6,
that is 4 in front of NH3 , 6 in front of NO, 5 in front of N2 and 6 in front of H2O
Answer :
The reactants are, [tex]4NH_3\text{ and }6NO[/tex]
The products are, [tex]5N_2\text{ and 6}H_2O[/tex]
Explanation :
Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.
The species present on the left side of the right arrow is the reactant and the species present on the right side of the right arrow is the product.
If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.
The coefficient tell us about that how many molecules or atoms present in the chemical equation.
The given chemical reaction is:
[tex]NH_3+NO\rightarrow N_2+H_2O[/tex]
This reaction is an unbalanced chemical reaction because in this reaction number of hydrogen atoms are not balanced.
In order to balance the chemical equation, the coefficient '4' put before the [tex]NH_3[/tex], the coefficient '6' put before the [tex]NO[/tex], the coefficient '5' put before the [tex]N_2[/tex] and the coefficient '6' put before the [tex]H_2O[/tex] and then we get the balanced chemical equation.
The balanced chemical reaction will be,
[tex]4NH_3+6NO\rightarrow 5N_2+6H_2O[/tex]
In this reaction:
The reactants are, [tex]4NH_3\text{ and }6NO[/tex]
The products are, [tex]5N_2\text{ and 6}H_2O[/tex]