Respuesta :

3rd that is it :( (hope this helps)

Answer:

The correct statement is:

[tex]\sqrt{\dfrac{5}{8}}[/tex] is irrational and [tex]\sqrt{\dfrac{4}{9}}[/tex] is a rational number

Step-by-step explanation:

We know that if we get a non-square term under a square root sign than that term is considered to be an irrational number.

We are given two numbers:

[tex]\sqrt{\dfrac{5}{8}}[/tex] and [tex]\sqrt{\dfrac{4}{9}}[/tex]

  • Now we know that:

[tex]\dfrac{5}{8}[/tex] is a non-square number.

Hence, on taking the square root of this number will give us a irrational number.

We can write it as:

[tex]\sqrt{\dfrac{5}{8}}=\dfrac{1}{2}\sqrt{\dfrac{5}{2}}[/tex]

( Since [tex]8=2^3=2^2\times 2[/tex])

  • Whereas:

[tex]\dfrac{4}{9}[/tex] could also be written as:

[tex]\dfrac{4}{9}=(\dfrac{2}{3})^2[/tex]

or

[tex]\dfrac{4}{9}=(\dfrac{-2}{3})^2[/tex]

Hence, on taking square root of this number will give us:

[tex]\sqrt{\dfrac{4}{9}}=\pm \dfrac{2}{3}[/tex]

which is a rational number.