Respuesta :
Answer:
The correct statement is:
[tex]\sqrt{\dfrac{5}{8}}[/tex] is irrational and [tex]\sqrt{\dfrac{4}{9}}[/tex] is a rational number
Step-by-step explanation:
We know that if we get a non-square term under a square root sign than that term is considered to be an irrational number.
We are given two numbers:
[tex]\sqrt{\dfrac{5}{8}}[/tex] and [tex]\sqrt{\dfrac{4}{9}}[/tex]
- Now we know that:
[tex]\dfrac{5}{8}[/tex] is a non-square number.
Hence, on taking the square root of this number will give us a irrational number.
We can write it as:
[tex]\sqrt{\dfrac{5}{8}}=\dfrac{1}{2}\sqrt{\dfrac{5}{2}}[/tex]
( Since [tex]8=2^3=2^2\times 2[/tex])
- Whereas:
[tex]\dfrac{4}{9}[/tex] could also be written as:
[tex]\dfrac{4}{9}=(\dfrac{2}{3})^2[/tex]
or
[tex]\dfrac{4}{9}=(\dfrac{-2}{3})^2[/tex]
Hence, on taking square root of this number will give us:
[tex]\sqrt{\dfrac{4}{9}}=\pm \dfrac{2}{3}[/tex]
which is a rational number.