y = x + 1
the equation of a line in slope-intercept form is
y = mx + c ( m is the slope and c the y-intercept )
y = - x + 11 is in this form with slope m = - 1
the slope of a perpendicular line = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-1}[/tex] = 1
y = x + c ← is the partial equation
to find c substitute (2, 3 ) into the partial equation
3 = 2 + c ⇒ c = 3 - 2 = 1
y = x + 1 ← equation in slope-intercept form