Question

An 8.50 L tire contains .552 lol of gas at a temperature of 305 K. What's the pressure , in atm and in psi, of the gas in the tire?

Answer 1

PV=nRT
P×8.5=0.552×0.082×305
8.5P=13,80552
$PV=nRT \\ P×8.5=0.552×0.082×305 \\ 8.5P=13,80552 \\ P = \frac{13,80552}{8.5} \\ P = 1.6 \: atm$