Question

WILL MARK BRAINLIEST FOR CORRECT ANSWER.

x = 6 is the solution for which equation?

A) $\frac{2}{3}$ x - 2 = $\frac{1}{3} x$

B) $\frac{2}{3} x$ + 2 = $\frac{1}{3} x$

C) $-\frac{2}{3} x$ - 2 = $\frac{1}{3} x$

D) $-\frac{2}{3} x$ + 2 = $\frac{1}{3} x$

Answer 1

I would simplify each equation and then plug in 6 for x.

A.) $\frac{2}{3}x-2= \frac{1}{3} x$  Subtract 2/3x on both sides

$\frac{2}{3}x-2- \frac{2}{3}x= \frac{1}{3}x-\frac{2}{3}x$

$-2=-\frac{1}{3}x$  Now you plug in 6

$-2=-\frac{1}{3} (6)$

$-2 = -\frac{6}{3}$

-2 = -2

x = 6 is the solution for choice A

Answer 2

Short Answer

It's A

Solution

A

2/3 x - 2 = 1/3 x                             Subtract 2/3x from both sides

2/3x - 2/3x - 2 = 1/3x - 2/3 x        Combine like terms

- 2 = - 1/3 x                                    Multiply both sides by - 3

- 2  * - 3 = 3 * - 1/3 x

- 6 = - x                                          Multiply by -1

x = 6

B

B looks like the same thing, but the 2 is a plus 2. When you solve for x you go through exactly the same steps. Your answer becomes - 6

C

C adds 2/3 x to both sides. The result is x = - 2

D same as C only x = 2