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What is the temperature in Celcius of 3.33 moles of neon that occupies 13.4 liters under the pressure of 3 atmospheres. Input your answer without units.

Respuesta :

Hey there!:

Number of moles = 3.33 moles of neon

Volume = 13.4 L

Pressure = 3 atm

R =  0.0821 L.atm/mol*K

Therefore:

T = 3.0 * 13.4 / 3.33 * 0.0821



T = 40.2 / 0.2734



T = 147 K


k in C :

ºC =  K - 273

147 - 273


T = - 126ºC


Hope that helps!