Question

Sum difference and product of two functions

Answer 1

Answer:

1)$(g+h)(x)=4x^2+x+2$

2) $(g-h)(x)=-4x^2+x+2$

3)$(g\bullet h)(-3)=-36$

Step-by-step explanation:

The given functions are

$g(x)=x+2$

and

$h(x)=4x^2$

1) $(g+h)(x)=g(x)+h(x)$

This implies that;

$(g+h)(x)=x+2+4x^2$

Rewrite  in standard form to obtain $(g+h)(x)=4x^2+x+2$

2) $(g-h)(x)=g(x)-h(x)$

This implies that;

$(g-h)(x)=x+2-4x^2$

Rewrite  in standard form to obtain $(g+h)(x)=-4x^2+x+2$

3) $(g\bullet h)(x)=(x+2)(4x^2)$

We now substitute $x=-3$ to obtain;

$(g\bullet h)(-3)=(-3+2)(4(-3)^2)$

$(g\bullet h)(-3)=(-1)(36)$

$(g\bullet h)(-3)=-36$