Respuesta :

Atomic number of O= 8

Atomic number of F = 9

Electron configurations:

⁸O = 1s² 2s² 2p⁴

⁹F = 1s² 2s² 2p⁵

Total electrons: 8+ 9 = 17

For OF the molecular electron configuration would be:

OF = (1σ)²(1σ*)²(2σ)²(2σ*)²(2pσ)²(2pπ)⁴(2pπ*)³

OF⁺ suggests a loss of one electron from the 2pπ* orbital leaving the configuration as:

OF⁺ = (1σ)²(1σ*)²(2σ)²(2σ*)²(2pσ)²(2pπ)⁴(2pπ*)²

Thus, based on MO theory there are two unpaired electrons in OF⁺ ion

There are two unpaired electron in the OF^+ ion.

According to the molecular orbital theory, the number of molecular orbitals formed is equal to the number of atomic orbitals that are overlapped. A molecular orbital is formed by the overlap of two atomic orbitals.

The molecular orbital configuration of OF^2+ is given by; (1σ)²(1σ*)²(2σ)²(2σ*)²(2pσ)²(2pπ)⁴(2pπ*)². Hence. there are two unpaired electron in the OF^+ ion.

Learn more about molecular orbitals: https://brainly.com/question/731147?

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