Question

The formula to determine the percent of hc2h3o2 (mass/volume) in vinegar is percent (m/v) = (grams of hc2h3o2/ volume of vinegar used (ml) ) x 100. if 5.0 ml of vinegar were used for the titration and 0.0042 moles of hc2h3o2 were required to reach the endpoint, calculate the percent of hc2h3o2 in vinegar. the molar mass of hc2h3o2 is 60.0 g / mol. question 10 options:

Answer 1

Answer: The percent of $HC_2H_3O_2$ in vinegar 5.04%.

Solution:

Given :

Moles of the $HC_2H_3O_2$ in 5 mL vinegar solution: 0.0042 moles

Molecular mass of the $HC_2H_3O_2$ = 60.0g/mol

$\text{Number of moles}=\frac{\text{Given mass of the substance}}{\text{Molecular mass of the substance}}$

Mass of $HC_2H_3O_2$ in 5 mL vinegar solution = $\text{Number of moles of}HC_2H_3O_2\times \text{Molecular mass of the}HC_2H_3O_2=0.0042mol\times 60.0g/mol=0.252 g$

The formula to determine the percent of $HC_2H_3O_2$ in vinegar :

$=\frac{\text{Mass of}HC_2H_3O_2\times 100}{\text{volume of vinegar used (ml)}}=\frac{0.252\times 100}{5 mL}=5.04\%$

So, The percent of $HC_2H_3O_2$ in vinegar 5.04%.