Question

A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a constant force (in contrast to the constant power in part a). if such a sports car went from zero to 29.0 mph in time 1.30 s , how long would it take to go from zero to 58.0 mph ?

Answer 1

The car would go from  zero to 58.0 mph in 2.6 sec.

Since the force on the car is constant, therefore the acceleration of the car would also be constant.

Now for constant acceleration we can use the equation of motion

Using first equation of motion to calculate the acceleration of the car

v=u+at

29=0+a×1.30       ...... Eq. (1)

Again using the first equation of motion

58=0+a*t             ....... Eq. (2)

Dividing eq. (2) with equation 1

t=2×1.3

t=2.6 sec

Answer 2

The time taken by the car to go from zero to 58.0 mph is 2.60 s

Given data:

The initial speed of car is, u = 0 m/s.

The final speed of car in first case is, v = 29.0 mph = 12.96 m/s.

Time taken in first case is, t = 1.30 s.

Final speed in second case is, v' = 58.0 mph = 25.92 m/s.

Apply the first kinematic equation of motion for the first case as,

$v=u+at$

Here, a is acceleration.

$12.96 =0+a \times 1.30\\a = 9.96\;\rm m/s^2$

Now, again apply the first kinematic equation of motion to second case as,

$v'=u'+at'\\25.92 = 0 +(9.96)t'\\t'=2.60 \;\rm s$

Thus, the time taken to go from zero to 58.0 mph is 2.60 s.

Learn more about the kinematic equations of motions here:

https://brainly.com/question/20423083?referrer=searchResults