1) for this problem you have to find the slope in first place of the given line
5x-2y = 10 ⇒2y = 5x-10⇒y =(5/2)x-5
now to calculate the intersection points of the line 5x-2y = 10, you do x= 0 and obtain -2y= 10 therefore y = -5, the point of intersection with the axis y is (0,-5)
2) in second place ,if two lines are parallels then the slopes must be equal for both
m1 = 5/2
3) with the equation point- slope you can find the equation
y-y1 = m(x-x1)
y-3 = 5/2(x-2)⇒ 2y-6 = 5(x-2)⇒2y-6= 5x-10⇒5x-2y = 4
to find the intersection point with axis x and y , we procedure of similar form as the previous line
if x = 0 then y = -2 the point will be (0,-2)
if y = 0 then x = 4/5 the point will be ( 4/5,0)
