Question

How many moles of silver (Ag) are present in a sample of 3.8 × 1024 atoms Ag?

Select one:
a. 1.6 mol Ag
b. 2.3 mol Ag
c. 6.3 mol Ag
d. 22.8 mol Ag

Answer 1

1 mol=6.022 x 10²³ atoms.

1 mol-----------------------------6.022 * 10²³ atoms
   x--------------------------------3.8 * 10²⁴ atoms

x=(1 mol * 3.8 * 10²⁴ atoms) / 6.022*10²³ atoms=6.3 moles of Ag,

Answer: C. 6.3 mol Ag

Answer 2

Answer : The correct option is, (C) 6.3 mole Ag

Explanation : Given,

Number of atoms of Ag = $3.8\times 10^{24}$

As we know that, 1 mole contains $6.022\times 10^{23}$ number of atoms.

As, $6.022\times 10^{23}$ number Ag atoms present in 1 mole of Ag

So, $3.8\times 10^{24}$ number Ag atoms present in $\frac{3.8\times 10^{24}}{6.022\times 10^{23}}=6.3$ mole of Ag

Therefore, the number of moles of Ag present are, 6.3 moles