write an algebraic expression for the interest earned on a $15000 deposit for a t months at 1.75% interest, compunded continuously

Respuesta :


Y=15000 e^(0.0175×t/12)


Y future value

15000 present value

E constant

1.75/100=0.0175 Interest rate

T time

12 number of months in a year


Hope it helps!

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