Question

The figure is made up of two cones and a cylinder. Both cones and the cylinder have a 10 mm diameter.

What is the exact volume of this figure?

What is the volume of this figure?


250π mm³

400π mm³

625π mm³

2500π mm³

Answer 1

Answer:

$625\pi\ mm^{3}$

Step-by-step explanation:

we know that

The volume of the figure is equal to the volume of two cones plus the volume of the cylinder

Find the volume of one cone

$V=\frac{1}{3}\pi r^{2} h$

we have

$r=10/2=5\ mm$ -----> the radius is half the diameter

$h=15\ mm$

substitute the values

$V=\frac{1}{3}\pi (5^{2})(15)=125\pi\ mm^{3}$

Find the volume of the cylinder

$V=\pi r^{2} h$

we have

$r=10/2=5\ mm$ -----> the radius is half the diameter

$h=15\ mm$

substitute the values

$V=\pi (5^{2})(15)=375\pi\ mm^{3}$

Find the volume of the figure

$2*125\pi\ mm^{3}+375\pi\ mm^{3}=625\pi\ mm^{3}$

Answer 2

Answer: 625π mm³

.

Step-by-step explanation:

Volume of cone = $\dfrac{1}{3}\pi r^2h$ , where r is radius and h is height of cone.

Volume of cylinder = $\pi R^2H$, where R is radius and H is height of cone.

For given picture,

Diameter of cone and cylinder = 10 mm , then radius = 5 mm (half of diameter)

h= 15 mm , r= 5mm

R= 5mm ,  H=15mm

Combined volume of figure = 2 x (Volume of cone)+ Volume of cylinder

$=2\times(\dfrac{1}{3}\pi (5)^2(15))+\pi (5)^2(15)\\\\=250\pi+375\pi\\\\=625\pi\ mm^3$

Hence, the volume of this figure is 625π mm³

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