Answer:
C) The two functions have the same x-intercept.
Step-by-step explanation:
The given function is
[tex]3x+2y=12[/tex]
Let's analyse this function. We can its elements, that is, its slope and y-intercept points by isolating [tex]y[/tex], as follows
[tex]3x+2y=12\\2y=12-3x\\y=\frac{12-3x}{2}\\ y=-\frac{3x}{2}+\frac{12}{2}\\ y=-\frac{3x}{2}+6[/tex]
So, the y-intercept is at [tex]y=6[/tex], which is not the same point showed in the graph. The slope of the linear equation is -3/2, which is not the same slope showed in the graph.
From the graph, we can deduct that te y-intercept is at [tex]y=4[/tex], and the slope is 1, because both variables increase at the same rate, which is 4 units, and if you divide 4/4 = 1.
At last, if we calculate the x-intecept of the linear equation, it would be
For [tex]y=0[/tex], let's find [tex]x[/tex]
[tex]3x+2y=12\\3x+2(0)=12\\x=\frac{12}{3}\\ x=4[/tex]
This means the x-intercept of the linear equation is at 4, and the graph shows the same x-intercept.
Therefore, the two functions have the same x-intercept. So, the right answer is C.