Question

Y=(x-1)^2-1
From vertex to standard form

Answer 1

The standard form:

$y=ax^2+bx+c$

We have $y=(x-1)^2-1$

Use $(a-b)^2=a^2-2ab+b^2$

$y=x^2-2(x)(1)+1^2-1\\\\y=x^2-2x+1-1\\\\\boxed{y=x^2-2x}\\\\a=1,\ b=-2,\ c=0$