Question

What size container do you need to hold 0.0459 mol of N2 gas at stp

Answer 1

Answer:

The size of the container needed is 1,03 liters

Explanation:

We use the formula PV=nRT. The STP conditions correspond to 1 atm of pressure and 273 K of temperature.

PV=nRT V=(nRT)/P

V= (0,0459 mol x 0,082 l atm/ K mol x 273K)/1 atm= 1,0275174 liters

Answer 2

The size of the container needed to hold the gas is 1.03 L

Data obtained from the question

• Number of mole (n) = 0.0459 mole
• Pressure (P) = STP = 1 atm
• Temperature (T) = STP = 273 K
• Gas constant (R) = 0.0821 atm.L/Kmol

• Volume (V) =?

How to determine the volume

The volume of the container needed can obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both side by P

V = nRT / p

V = (0.0459 × 0.0821 × 273) / 1

V = 1.03 L

Therefore, the size of the container needed is 1.03 L.

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