Question

5/x-2 - 2/3x-5

$\frac{5}{x-2} - \frac{2}{3x-5}$

Answer 1

All we need to do is to have the same denominator
5/x-2 - 2/3x-5
$\frac{5}{x-2}$×$\frac{3x-5}{3x-5}$ -$\frac{2}{3x-5}$×$\frac{x-2}{x-2}$
$\frac{15x-25}{(x-2)(3x-5)}$ - $\frac{2x-4}{(x-2)(3x-5)}$
Answer = $\frac{(15x-2x-25-4)}{(x-2)(3x-5)}$
             = $\frac{13x-29}{(x-2)(3x-5)}$