Question

PLEASE HELP ME PLEASE!!!!!!!!
If 3.00 g of CH3OH is reacted with excess sulfuric acid and the actual yield of (CH3)2SO4 was 0.94 g, what was the percent yield of the reaction?

2 CH3OH + H2SO4 → (CH3)2SO4 + H2O

Answer 1

So yield = actual/predicted*100

You need to find the theoretical yield. CONVERT INTO MOLES. this is the 1st step you do in most calculation questions.

I got 15.92%