Question

What average force is required to stop a 950 kg car in 8.0s if the car is traveling at 95 km/h

Answer 1

Answer:

   Force required to stop car = 3.13 kN

Explanation:

 Force required = Mass of car x Acceleration of car

 Acceleration of car = Change in velocity of car / Time.

 Mass of car, m=   950 kg

 Acceleration of box, a = (95 - 0)/8 = 11.875 kph per second

                                       $=\frac{11.875*1000}{60*60} =3.30m/s^2$

  Force required = ma

                             = 950 x 3.30 = 3133.68 N = 3.13 kN

  Force required to stop car = 3.13 kN

Answer 2

The average force required to stop the car is -3125.5 N.

Given data:

The mass of car is, m = 950 kg.

The time taken to stop the car is, t = 8.0 s.

Initial speed of car is, u = 95 km/h = 26.38 m/s.

Final speed of car is, v = 0 m/s. (As car is required to stopped finally)

Apply the first kinematic equation of motion to calculate acceleration (a) as,

$v = u +at\\0=26.38+ a(8.0)\\a=\dfrac{-26.38}{8}\\a=-3.29 \;\rm m/s^{2}$

Now, the average force required to stop the car is,

$F = m \times a\\F =950 \times (-3.29)\\F = -3125.5 \;\rm N$

Thus, the average force required to stop the car is -3125.5 N.

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