For this case we have:
By trigonometric property we have:
[tex]Cosine(\alpha)=\frac{AdjacentLeg}{Hypotenuse}[/tex]
Where:
[tex]Adjacent Leg = 12\\Hypotenuse = 13\\\alpha= x[/tex]
Substituting:
[tex]Cosine(x)=\frac{12}{13}[/tex]
Clearing x we have:
[tex]x =Cosine^{-1}(\frac{12}{13})[/tex]
Thus, the equation is: [tex]x =Cosine^{-1}(\frac{12}{13})[/tex]
Answer:
[tex]x =Cosine^{-1}(\frac{12}{13})[/tex]
