Respuesta :

Answer:

  48√7

Step-by-step explanation:

  [tex]\sqrt{32}\cdot\sqrt{28}\cdot\sqrt{3}\cdot\sqrt{6}=\sqrt{(2^5)(2^2\cdot 7)(3)(2\cdot 3)}\\\\=\sqrt{(2^4\cdot3)^2(7)}=2^4\cdot 3\sqrt{7}=\boxed{48\sqrt{7}}[/tex]

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