[tex]\left\{\begin{array}{ccc}y=x-10&(1)\\2x+y=4&(2)\end{array}\right\\\\\text{substitute (1) to (2)}\\\\2x+(x-10)=4\\(2x+x)-10=4\qquad|\text{add 10 to both sides}\\\\3x=14\qquad|\text{divide both sides by 3}\\\\x=\dfrac{14}{3}\\\\\text{put the value of x to (1)}\\\\y=\dfrac{14}{3}-10\\\\y=\dfrac{14}{3}-\dfrac{30}{3}\\\\y=-\dfrac{16}{3}\\\\Answer:\ x=\dfrac{14}{3}\ and\ y=-\dfrac{16}{3}[/tex]
