Answer:
y = (x + 2)^2 - 7
Step-by-step explanation:
The vertex form of the equation of a parabola (such as we have here) is y = a(x-h)^2 + k, where (h,k) is the vertex. It's safe to assume that the coefficient "a" in y=x^2+4x-3 is 1.
The best thing to do now is to complete the square.
That is, y = x^2 + 4x + 4 - 4 -3
This can be re-written in more compact form as:
y = (x + 2)^2 - 7
Comparing this to
y = a(x-h)^2 + k
shows that h = -2 and k = -7, which leads to the conclusion that the vertex is at (-2, -7).
