Respuesta :
weight of the block is given as 40 N
so we have
mg = 40 N
m* 9.8 = 40
[tex]m = \frac{40}{9.8}[/tex]
[tex]m = 4.1 kg[/tex]
now by Newton's II law we know that
[tex]F - F_f = ma[/tex]
given that
F = 60 N
[tex]F - F_f = ma[/tex]
[tex]60 - F_f = 4.1*8[/tex]
[tex]F_f = 60 - 4.1*8[/tex]
[tex]F_f = 27.2 N[/tex]
so friction force will be 27.2 N
F = applied force on the block = 60 N
W = weight of the block = 40 N
a = acceleration of the block in horizontal direction = 8 m/s²
f = frictional force acting in opposite direction of applied force = ?
m = mass of the block
g = acceleration due to gravity = 9.8 m/s²
mass of the block is given as
m = W/g
m = 40/9.8
m = 4.08 kg
from the force diagram , force equation for the motion of the block is given as
F - f = ma
inserting the values
60 - f = (4.08) (8)
60 - f = 32.5
f = 60 - 32.5
f = 27.5 N
hence the force of friction is 27.5 N
