What is the equation of the line in slope-intercept form?

Line on a coordinate plane. The line runs through points begin ordered pair negative 2 comma 0 end ordered pair and begin ordered pair 0 comma 5 end ordered pair.

What is the equation of the line in slopeintercept form Line on a coordinate plane The line runs through points begin ordered pair negative 2 comma 0 end ordere class=

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Answer:

[tex]f(x)=\frac{5}{2}x+5[/tex]

Step-by-step explanation:

1)Given two points (-2,0) and (0,5) let's find the slope, then the equation of the line, in slope-intercept form. Notice the last parameter to be found was the linear parameter "b" :

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{5-0}{0+2}=\frac{5}{2}\Rightarrow \left\{\begin{matrix}0 =&\frac{5}{2}(-2)&+b \\ 5=& \frac{5}{2}(0) &+b\\ \end{matrix}\right.\Rightarrow b=5 \therefore f(x)=\frac{5}{2}x+5[/tex]

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