Question

find the solution(s) to (x+3)^2=49 check all that apply

Answer 1

 

$\displaystyle\\(x+3)^2=49\\\\(x+3)^2=7^2\\\\x+3 = \pm 7\\\\\text{If}~~x+3 = 7 ~\text{then}~x = 7-3~\Longrightarrow~~\boxed{x=4}\\\\\text{If}~~x+3 = -7 ~\text{then}~x = -7-3~\Longrightarrow~~\boxed{x=-10}$

Answer 2

The solutions to the equation $(x+3)^{2}$ = 49 are 4 and -10.

How to solve the given quadratic equation in x ?

Given equation is  $(x+3)^{2}$ = 49

Solving the quadratic equation -

⇒ (x + 3) = √49

⇒ (x + 3) = ±7

We get two solutions from the above equation,

First solution is -

⇒ (x + 3) = +7

∴  x = 7 - 3 = 4

Second solution is -

⇒ (x + 3) = -7

∴  x = -7 - 3 = -10

Thus the solutions to the equation $(x+3)^{2}$ = 49 are 4 and -10.

To learn more about quadratic equation, refer -

https://brainly.com/question/1214333

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