Question

How many lemon shakeups would they need to sell to earn $1,000

Answer 1

I think a good way to go about this problem is to construct a line for which we can find where l = 1000 and the profit (p) associated with it. To find the equation of our line, we are going to use the point-slope formula, which is listed as follows:

$(y - y_1) = m(x - x_1)$

• $m$ is the slope of the line
• $(x_1, y_1)$ is a coordinate point on the line

We know we have the point (250, 50), so we have part of the equation now. The slope of this line would be

$m = \dfrac{200 - 50}{300-250} = \dfrac{150}{50}  = 3$

Now, "plugging in" our information into the point-slope formula, we get the equation:

$(y - 50) = 3(x - 250)$

$(y - 50) = 3x - 750$

$y = 3x - 700$

We are going to change $x$ to $l$ since $l$ is the independent variable in the problem and we are going to change $y$ to $p$ since $p$ is the dependent variable in this problem. Our equation is now

$p = 3l - 700$

Now, we are trying to solve for when $p = 1000$, or the amount of lemon-shake ups they would need to sell $1000. Thus, let's substitute $p = 1000$ into our equation and solve for $l$:

$1000 = 3l - 700$

$1700 = 3l$

$l = \dfrac{1700}{3}$

Technically, they would need to sell 1700/3 lemon-shake ups to earn $1,000. However, if they are not able to sell part of a lemon-shake up, then we would need to round to the nearest whole number, which would be 567 lemon-shake ups.

Answer 2

Ummmm cant see the pic