From given graph we see that points forms a parabolic shape that means we can use quadratic model to find the equation whose formula is given by:
[tex]y=a(x-h)^2+k[/tex]
where (h,k) represents vertex.
From graph we see that vertex is (3,49).
Hence h=3 and k=49
Plug these values into above formula
we get:
[tex]y=a(x-3)^2+49[/tex]
Now we need to find the value of a, so we can plug any point say (5,45) then we get:
[tex]45=a(5-3)^2+49[/tex]
[tex]45=a(2)^2+49[/tex]
[tex]45=4a+49[/tex]
[tex]45-49=4a[/tex]
[tex]-4=4a[/tex]
[tex]-1=a[/tex]
Plug value of a, h and k into above formula, we get:
[tex]y=-1(x-3)^2+49[/tex]
[tex]y=-1(x^2-6x+9)+49[/tex]
[tex]y=-x^2+6x-9+49[/tex]
[tex]y=-x^2+6x+40[/tex]
which best matches with first choice
Hence final answer is [tex]R(x)=-x^2+6x+40[/tex]