The volume of ideal gas that would occupy at 1.50 atm and 216 c is
2016.49 ml
calculation
that is P1V1/T1= P2V2/T2
P1( pressure 1) = 7.20 atm
V1 ( volume 1) = 250 ml
T1 ( temperature 1) = 18 + 273=291 K
P2 ( pressure 2) = 1.50 atm
T2 ( temperature 2)= 216+273=489 K
V2 ( volume 2) =?
V2=[(T2 xP1 x V1)/(T1 xP2)]
V2=[ (489 K x 7.20 atm x 250 ml) / ( 291 k x 1.50 atm)] = 2016.49 Ml