Respuesta :

amyy5
no

it's 6w(squared)-2w
DeanR

No, sorry, that's not correct.  

2w(3w - 1)

We dstribute the 2w factor

= (2w)(3w) - 2w(1)

then we multiply out each term,

= 6w² - 2w

and we can stop here.


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