Question

Subject to some of (3/5 + 1/5i) and (4/5 - 2/5i) from (9/5 - 1/5i). the result is what

Answer 1

The correct answer is: 2/5.

Explanation:

First you have to add the following expressions:

$(\frac{3}{5}+\frac{1}{5}i)+(\frac{4}{5}-\frac{2}{5}i) \\ (\frac{3}{5}+ \frac{4}{5})+(\frac{1}{5}i-\frac{2}{5}i) \\= \frac{7}{5}-\frac{1}{5}i$

Now subtract the above expression from $(\frac{9}{5}-\frac{1}{5}i)$:

$(\frac{9}{5}- \frac{1}{5}i) - (\frac{7}{5} -\frac{1}{5}i) \\ (\frac{9}{5} -\frac{7}{5}) + (\frac{1}{5}i -\frac{1}{5}i) \\ \frac{2}{5}$

Hence the correct answer is 2/5.

Answer 2

Answer:

Result = 2/5

Step-by-step explanation:

Question: Subtract to sum of (3/5 + 1/5i) and (4/5 - 2/5i) from (9/5 - 1/5i).

First we will take sum of  (3/5 + 1/5i) and (4/5 - 2/5i):

(3/5 + 1/5i) + (4/5 - 2/5i)

= 3/5 + 1/5i + 4/5 - 2/5i

= 3/5 + 4/5) + (1/5i - 2/5i)

= (7/5 - 1/5i)

Now subtract (7/5 - 1/5i) from (9/5 - 1/5i).

(9/5 - 1/5i) - (7/5 - 1/5i)

= 9/5 - 1/5i - 7/5 -1/5i

=  (9/5 - 7/5) - (1/5i + 1/5i)

= (2/5) - 0

= 2/5

                                   Result = 2/5