Question

3 exponet 8×4+9÷1×56+57

Answer 1

You would use PEMDAS

But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57

Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57

Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57

Now you can add all of the numbers together
32➕504=536
536➕57=593

Your answer is 593

Hope this helps! :3