Answer:
324,632 possible combinations
Step-by-step explanation:
We are looking for the amount of combinations of 5 students we can have in a class of 35 students. We write this as 35_C_5. The formula for finding the number of combinations of x objects from a set of y objects is x_C_y = [tex]\frac{x!}{y!*(x - y)!}[/tex].
Then we have:
35_C_5 = [tex]\frac{35!}{5!*(30!)}[/tex]
[tex]\frac{1.0333148*10 ^40}{120*2.6525286*10^32}[/tex] --- expand
[tex]\frac{1.0333148*10^40}{3.1830343*10^34}[/tex] --- simplify
324,632 --- simplify
324,632 possible combinations
