Answer:
[tex]f^{-1}(x)=9x-18[/tex]
Step-by-step explanation:
we have
[tex]f(x)=\frac{1}{9}x+2[/tex]
Let
[tex]y=f(x)[/tex]
[tex]y=\frac{1}{9}x+2[/tex]
Exchange variables x for y and y for x
[tex]x=\frac{1}{9}y+2[/tex]
Isolate the variable y
[tex]x-2=\frac{1}{9}y[/tex]
[tex]y=9(x-2)[/tex]
[tex]y=9x-18[/tex]
Let
[tex]f^{-1}(x)=y[/tex]
[tex]f^{-1}(x)=9x-18[/tex] -------> inverse function