[tex]\dfrac{3}{5}=\dfrac{3\cdot2}{5\cdot2}=\dfrac{6}{10}\\\\\dfrac{1}{2}=\dfrac{1\cdot5}{2\cdot5}=\dfrac{5}{10}\\\\\dfrac{3}{5}+\dfrac{1}{2}=\dfrac{6}{10}+\dfrac{5}{10}=\dfrac{6+5}{10}=\dfrac{11}{10}=1\dfrac{1}{10}\\\\\dfrac{3}{5}-\dfrac{1}{2}=\dfrac{6}{10}-\dfrac{5}{10}=\dfrac{6-5}{10}=\dfrac{1}{10}[/tex]
