Given that the equation of distance "x" of a car travelling in a straight line along a road.
x(t) = 9 t² - 8 t³ meters
acceleration at time "t" = ?
t = 4.6 s
Acceleration = Velocity/ time
Velocity = distance/ time
Acceleration = distance / time²
Acceleration = x / t²
a (t) = (9t² - 8t³)/ t²
a (t) = 9 - 8t
a (4.6) = 9 - 8 (4.6)
a (4.6) = -27.80 m/s²
The acceleration of car at time "t" is 27.80 m/s².
