Question

Physic its urgent
1/ What is the total distance traveled by the object during the first 3 second

2/What is the average speed of the object during the following interval in t=6 sec and t= 8 sec

Answer 1

(1) Distance = speed × time

Total distance = 10m/sec × 3sec = 30m

(2) Average speed = (25m/sec + 10m/s) ÷ 2 = 17.5m/sec

Answer 2

(1) The distance covered by the object within the given time period is 30 m.

(2) The average speed of the object for the time period is 16.43 m/s.

(1) From the given graph, the speed of the object during the first 3 seconds is given as;

• speed of the object = 10 m/s

The distance of the object is the product of the speed and the time of motion.

         Distance = speed x time

         Distance = 10 x 3

         Distance = 30 m

Thus, the distance covered by the object within the given time period is 30 m.

(2) The speed of the object for the different time intervals is given as;

• when the time is 6 s, v = 25 m/s

• when the time is 8 s, v = 10 m/s

The average speed is calculated as;

$average \ speed = \frac{total \ distance}{total \ time } \\\\v = \frac{(6\times 25) + (8\times 10)}{6 + 8} \\\\v = 16.43 \ m/s$

Thus, the average speed of the object for the time period is 16.43 m/s.

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