there are 25 players on the team (10+6+9)
there are 6 infielders
They are picking without replacement
6/25 * 5/24 * 4/23
rearranging
6*4/24 *5/25 *1/23
1 *1/5 *1/23
1/115
Answer: 1/115
Answer:[tex] \frac{1}{115}[/tex]
Step-by-step explanation:
Given
there is 10 pitchers,6 infielders and 9 other players
3 players are selected at random
no of ways in which 3 infielders can be selected is [tex]^6C_3[/tex]
no of ways in which 3 players out of 25 players can be selected is
[tex]^{25}C_3 [/tex]
Therefore required probability is [tex]\frac{^6C_3}{^25C_3}=\frac{1}{115}[/tex]