please i need to know if im correct with these questions
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Answer: No Solution
Step-by-step explanation:
ln x - ln (x + 2) = 4 restrictions: x > 0 and x + 2 > 0 → x > 0
ln [tex](\frac{x}{x + 2})[/tex] = 4
[tex](\frac{x}{x + 2})[/tex] = e⁴
x = e⁴ (x + 2)
x = 54.5982 (x + 2)
x = 54.5982x + 109.1964
- 53.5982x = 109.1964
x = [tex]\frac{109.1964}{-53.5982}[/tex]
x = -2.0373
-2.0373 is not greater than 0 so is not valid
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Answer: 2.1972
Step-by-step explanation:
eˣ = 9
ln eˣ = ln 9
x = ln 9
x ≈ 2.1972
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Answer: [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
log₂ (3x - 4) = -1
3x - 4 = 2⁻¹
3x - 4 = [tex]\frac{1}{2}[/tex]
+4 +4
3x = [tex]4\frac{1}{2}[/tex]
3x = [tex]\frac{9}{2}[/tex]
[tex]\frac{3x}{3} = \frac{9}{2} * \frac{1}{3}[/tex]
x = [tex]\frac{3}{2}[/tex]
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Answer: 1.117519
Step-by-step explanation:
in the calculator, type in 1 ÷ 9.
Then hit the eˣ button.
e¹⁾⁹
= e°¹¹¹¹¹¹
= 1.117519
rounded to 6 decimal places: 1.117519