How to find a and b? (Pascal's triangle)
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Pascal's triangle is symmetric, so the first line is actually
5005 a a 5005
and the second line is actually
. b 12870 b .
Moreover, in Pascal's triangle, each term is between two terms in the previous rows, and it turns out be their sum. So, you have
[tex] 2a = 12870 \iff a = 6435 [/tex]
and also
[tex] b = a+5005 = 6435+5005=11440[/tex]
The two 5005s tell us we're in the middle of Pascal's triangle, which has bilateral symmetry.
So we can add the a and b labels to two other points by the symmetry as shown.
The two equations we can write are then
5005 + a = b
a + a = 12870
a = 12870/2 = 6435
b = 5005 + 6535 = 11540
Answer: a=6435, b=11540
Check:
Those are right, they happen to be
[tex]{15 \choose 6} = {15 \choose 9} = 5005 [/tex]
[tex]{15 \choose 7} = {15 \choose 8} = 6435 [/tex]
[tex]{16 \choose 8}= 12870[/tex]
[tex]{16 \choose 7} = {16 \choose 9} = 11440[/tex]