for the truck :
M = mass of the truck = 20000 kg
V = speed of truck = 110 km/h = 110 (km/h) (1000 m/1 km) (1 h/3600 sec) = 30.6 m/s
kinetic energy of truck is given as
KE₁ = (0.5) M V²
inserting the values
KE₁ = (0.5) (20000) (30.6)² = 9363600 J
for the astronaut :
m = mass of astronaut = 80 kg
v = speed of astronaut = 27500 km/h = 27500 (km/h) (1000 m/1 km) (1 h/3600 sec) = 7638.9 m/s
kinetic energy of astronaut is given as
KE₂ = (0.5) m v²
inserting the values
KE₂ = (0.5) (80) (7638.9)²
KE₂ = 2.33 x 10⁹ J
Ratio of kinetic energy of truck with kinetic energy of astronaut is given as
KE₁ /KE₂ = (9363600)/(2.33 x 10⁹)
KE₁ /KE₂ = 0.00402
kinetic energy of truck is 0.00402 time the kinetic energy of astronaut.
The difference in the two kinetic energy is 2.32 x 10⁹ J .
The kinetic energy of the truck is calculated as follows;
K.E = ¹/₂mv²
where;
v is the velocity = 110 km/h = 30.56 m/s
K.E = 0.5 x 20,000 x 30.56²
K.E = 9,339,136 J
The kinetic energy of the astronaut is calculated as follows;
K.E = 0.5 x 80 x (7638.889)²
K.E = 2.334 x 10⁹ J
The difference in the two kinetic energy is calculated as follows;
K.E = 2.334 x 10⁹ J - 9,339,136 J = 2.32 x 10⁹ J
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