Question

To evaluate an expression with variables: 1. Substitute the values for the variables. 2. Identify grouping symbols, beginning with the innermost symbols. 3. Determine and apply the rules of exponents to simplify. 4. Evaluate. Evaluate the expression using x = –1 and y=3. (6x4y3) What is the value of the expression?

Answer 1

Evaluate the expression using x = –1 and y=3.

$(6x^4y^3)$

1. Substitute the values for the variables.

we plug in -1 for x  and 3 for y

$(6x^4y^3)$

$(6(-1)^4(3)^3)$

2. Identify grouping symbols, beginning with the innermost symbols.

$(6*(-1)^4*(3)^3)$

We take exponent and then we multiply

3. Determine and apply the rules of exponents to simplify

$(6*(-1)^4*(3)^3)$

(-1)^4 = -1 * -1 * -1 * -1 = 1

(3)^3 = 3*3*3= 27

$(6*(1)*(27))$

4. Evaluate.

$(6*(1)*(27))$

162

The value of the expression is 162

Answer 2

Using the principle of substitution, the value of the expression given is 162.

Given the expression :

• 6x⁴y³

x = -1 ; y = 3

Substituting the values into the expression :

6(-1)⁴(3)³

• -1⁴ = - 1 × - 1 × - 1 × - 1 = 1
• 3³ = 3 × 3 × 3 = 27

6(1)(27) = 6 × 1 × 27 = 162

Hence, the value of the expression is 162.

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