Hello!
To find the linear equation written in slope-intercept form, we need to recall the slope-intercept form equation. That equation is y = mx + b. In this equation, m is the slope and b is the y-intercept.
We are given the slope, which is -5, and a point on the given graph, which is (-1, -8). So, we can substitute m = -5 into the equation, and the ordered pair, which allows you to solve for b.
y = mx + b (substitute m = -5, and (-1, -8))
-8 = -5(-1) + b (multiply)
-8 = 5 + b (subtract 5 from both sides)
-13 = b | The y-intercept is -13.
Therefore, the linear equation is y = -5x - 13.
The linear equation in slope-intercept form is [tex]y = -5x-13[/tex]
Given that,
A linear equation in slope-intercept form with a slope of -5 and passes through the point (-1,-8).
We have to determine,
The linear equation.
According to the question,
To find the linear equation written in slope-intercept form, the slope-intercept form equation.
That equation is y = mx + b.
In this equation, m is the slope and b is the y-intercept.
To find the value of b substitute the value of m = -5 and points (-1, -8) in the standard linear equation,
[tex]y = mx + b\\\\-8 = (-5)(-1) + b\\\\-8 = 5 + b\\\\b = -8-5\\\\b = -13[/tex]
The y-intercept is -13.
Therefore, The linear equation is [tex]y = -5x-13[/tex]
To know more about the Linear equation click the link given below.
https://brainly.com/question/13788907
