Zoe801 Zoe801
  • 19-10-2018
  • Mathematics
contestada

What are the solutions to the equation over the complex numbers?

x2+48=0

x = or x =

Respuesta :

jdoe0001 jdoe0001
  • 19-10-2018

[tex]\bf x^2+48=0\implies x^2=-48\implies x=\pm\sqrt{-48}~~\begin{cases}48=2\cdot 2\cdot 2\cdot 2\cdot 3\\\qquad 2^2\cdot 2^2\cdot 3\\\qquad (2^2)^2\cdot 3\\\qquad 4^2\cdot 3\end{cases}\\\\\\x=\pm\sqrt{-1\cdot 4^2\cdot 3}\implies x=\pm\sqrt{-1}\cdot \sqrt{4^2\cdot 3}\implies x=\pm i4\sqrt{3}[/tex]

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