Respuesta :

gmany

We know:

[tex]\tan\Theta=\dfrac{\sin\Theta}{\cos\Theta}[/tex]

We have:

[tex]\sin\Theta=\dfrac{\sqrt3}{2},\ \cos\Theta=\dfrac{1}{2}[/tex]

Substitute:

[tex]\tan\Theta=\dfrac{\frac{\sqrt3}{2}}{\frac{1}{2}}=\dfrac{\sqrt3}{2}:\dfrac{1}{2}=\dfrac{\sqrt3}{2}\cdot\dfrac{2}{1}=\sqrt3[/tex]

Answer: a. √3

tan theta = sin theta/ cos theta

tan theta = sqrt (3)/2 divided by 1/2

               = sqrt (3)/2 * 2/1

              sqrt(3)