Question

Identify the zeros for the function and sketch a graph. y=x(x-2)(x+3)

x=0.x=2,x=-3

x=0,x=-2,x=3

Answer 1

The product is equal to zero if one of the factors is equal to zero.

Therefore:

$y=x(x-2)(x+3)\\\\x(x-2)(x+3)=0\iff x=0\ \vee\ x-2=0\ \vee\ x+3=0\\\\\boxed{x=0\ \vee\ x=2\ \vee\ x=-3}$