Given that,
Weight of man, W= 650 N
Upward force by elevator, F= 620 N
a = ?
Since,
W = mg
m= W/g =650/9.81
m = 66.25 kg
Since,
F = ma
a = F/m
a = 620/66.25
a = 9.35 m/s²
Acceleration will be 9.35 m/s².
Since the force is in upward direction, it will accelerate the body in upward direction.
Answer:Man's acceleration is 0.452 [tex]\frac{m}{s^{2}}[/tex] in downward direction
Explanation:
Weight of man, W= 650 N
Normal force exerted by floor of elevator , N= 620 N
Since weight , W = mg
mass m= [tex]\frac{W}{g}=\frac{650}{9.8}kg[/tex]
Using Newtons 2nd law
W-N= ma where a= acceleration of man in the downward direction
=> 650-620=[tex]\frac{650}{9.8}kg\times a[/tex]
=> a= 0.452 [tex]\frac{m}{s^{2}}[/tex] in downward direction
